KingCondanomation
New member
Ok so here is the answer, A takes a knife stabs B and C and devours all the cake.
Ok so here is the answer, A takes a knife stabs B and C and devours all the cake.
A cuts
B chooses A's portion
C chooses C's portion
The number of pieces would be equal, but not the volume of cake.
Each of the 12 pieces would be .08333333 of the whole cake, except for one piece, which would have to be .08333334 to include the entire whole cake. Of course, none of the recipients would be able to tell the difference in a piece of cake .00000001 larger or smaller than the others.
Ah, the Obama plan.you have all overlooked the obvious.....the government takes the cake and give all three crumbs...
Ah, the Obama plan.
3 people are dividing a cake. Each person wants as much cake as possible for himself, but each person thinks that the other two might be colluding. Lets call the three A, B, and C.
A suggests that he will cut the cake into 3 portions, and then C will pick his piece from the 3, and B then would pick his choice from the 2 remaining. and A takes the last piece. B objects to this scheme, saying that A can cut the cake into 1 large piece, and 2 smaller equal pieces. C then would have the largest piece, and B would have to take the smaller piece. In fact, B claims, If A and C were really colluding, this method would allow them to get the entire cake to share among the two of them.
Given this distrusting atmosphere, is there a way to divide the cake so that each person is satisfied? Any proposed method would have to convince each person that he would get his fair share even if the other two were colluding.
Ok seriously, here is how you do it.
Let's make the cake rectangular, although it doesn't matter, it's easier to visualize the solution.
A holds his knife facing north to south (or straight out) and moves his knife very slowly hovering from the top of the east corner towards the top west corner.
At any time A can start cutting north to south and take his piece, or before that B or C can yell "Stop" and at that point A has to cut (north to south) and then whoever yelled stop has to take that piece. Then out of the 2 remaining people without cake, one starts the same hovering movement with the knife and he can start cutting his piece whenever he wishes unless the last person yells stop once more in which case he has to take the piece. The final piece goes to whoever is left.
This is prone to human error of course as the person who holds the knife could cut early and get a smaller piece or the person watching waiting to possibly yell stop could say stop too early and get a smaller piece. But in the end they all have control over how it is cut so it is fair and if they all want the biggest piece and have a keen eye they will end up with 3 equal pieces.
There is no way to collude or cheat anyone.
The number of pieces would be equal, but not the volume of cake.
Each of the 12 pieces would be .08333333 of the whole cake, except for one piece, which would have to be .08333334 to include the entire whole cake. Of course, none of the recipients would be able to tell the difference in a piece of cake .00000001 larger or smaller than the others.