That shouldn't matter. The figure isn't the percentage of disenfranchised people who are black (which would be expected to be low in a state with few black people), but rather the percentage of blacks who are disenfranchised. Even if a place only had four black people, if one of them was disenfranchised, that would be 25%.
The reason, instead, is that Maine and Vermont don't disenfranchise people -- they both are at 0% for the whole population, as well. The states with high rates for blacks have high rates for people overall, too (just not as high). For example, 9.14% of people from Kentucky have been disenfranchised.
PoliTalker (11-16-2018)
This is one argument for affirmative action. The idea is that if you seed underprivileged communities with successful people, you can alter the underlying culture in a positive way (e.g., providing role models within that community who can have an out-sized effect on those around them).
Jack (11-15-2018)
The rules Republicans focus on creating are rules specifically designed to decrease turnout among blacks. For example, when it comes to qualifying voter ID, Republicans tend to be fine with allowing ID that is disproportionately held by whites (e.g., driver's licenses, gun licenses), but not ID that is disproportionately held by blacks (say, an EBT card).
This is just a wild guess, but I wouldn't be at all surprised if liberals paid more taxes, per capita, than conservatives. Conservatives are disproportionately likely to fall into a few categories where effective tax rates are lower. One are business owners, who can use all sorts of tricks to lower their tax liability. If you have a guy whose business earns $150,000 and a person who earns the same $150,000 in the form of salary for a professional job, the latter is likely to pay more in taxes, since he'll be on the hook for payroll taxes and less able to play games to reduce taxable income (legally or otherwise).
Another category are retirees, who earn most of their money at the lower investment rates, rather than income tax rates like younger earners.
There's been a consistent faction within this country that has been aligned with white supremacist goals: southern, rural, conservative, states-rights whites. The name of that faction has changed over time. They were once the anti-Federalists. Then the Democratic Republicans. Then the Democrats. Then the Republicans. But regardless of what label they had at a given moment, you'd find the same basic collection of states, localities, and demographic groups in that faction. For example, compare the 1900 and 2000 election maps, and you'll see they're pretty close to identical, just with the colors flipped. The grandkids and great-grandkids of the racist Democrats of the early 20th century are the racist Republicans of the early 21st century.
Done. Here's a detail for Maine:
https://www.sentencingproject.org/th...set-option=SIR
As you can see, the disenfranchised population is 0, and the disenfranchised African American population is also 0, consistent with my statement. By comparison, see Kentucky:
https://www.sentencingproject.org/th...set-option=SIR
As you can see, that lists the disenfranchised African American population as 26.15% of the African American population.
Like I stated, ya might want to actually read the site.
The population in Maine consists of only 1.5% AA. In Maine the incarceration rate for AA is 6:1.
IN KY the incarceration rate is 3:1 disparity.
Maine simply does not have enough people to qualify for the number of people out of 100,000. That is why their rate is low. The MAX number it could be for AA in Maine is 1... the MAX is 1.
take a good hard look at the northeast numbers on incarceration rates of blacks vs whites. A lot higher than the southern states.
https://www.sentencingproject.org/th...set-option=BWR
I did. I even pointed out the exact data confirming my point.
I think you're missing the point. Let's imagine that 0.375% of the total population consists of disenfranchised African Americans. Then 25% of African Americans in Maine would be disenfranchised. Instead, it's 0%, according to that site. The fact that the denominator there is so small isn't really material, because it just means a very small numerator can create a high percentage.The population in Maine consists of only 1.5% AA.
I would recommend you actually read the site and THEN comment on it. They list the raw number in every state, down to the last digit. In Kentucky, the number of disenfranchised African Americans is 69,771. In Maine, it's 0. Since Maine has more than zero African Americans, you can use those two figures to calculate a percentage, and it's 0%.Maine simply does not have enough people to qualify for the number of people out of 100,000.
No. That's not how the math works. Take Montana, for example. Montana is about 0.4% black:That is why their rate is low. The MAX number it could be for AA in Maine is 1... the MAX is 1.
https://en.wikipedia.org/wiki/List_o...can_population
Yet, according to the disenfranchisement site, 2.07% of their African Americans are disenfranchised. Using your logic, that's over five times as high as is mathematically possible. Similarly, Idaho is 0.6% black, yet 6.98% of their African Americans are disenfranchised. Wyoming is the most dramatic example. They're about 0.8% black, yet 17.18% of their African American population is disenfranchised. All those places have lower black populations than Maine, yet all have much, much higher percentages of disenfranchised African Americans.
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