ZenMode
Well-known member
Right, and you continue to avoid recognizing that all substances absorb IR, you continue to avoid answering my question about the temperature of an oxygen and/or nitrogen cloud in close proximity to the sun, you refuse to acknowledge that your favorite parlor trick is based on getting the gullible audience to play pretend that a candle or a lamp somehow "represents" the sun's full range of bandwidth and you continue to delude yourself into denial as to why your favorite parlor trick is never performed outdoors in the sun (i.e. allowing the sun to actually "represent" the sun) because that would totally ruin the trick.
"Evidence" is not the correct word. Magicians don't like to reveal their secrets, and the illusionists who perform your favorite parlor trick similarly don't like the secrets behind the trick being revealed. I'll reveal them anyway. That initial narrative at the beginning that talks about the sun is just setting you up for a bait-and-switch. The magician will not walk you outdoors to perform any demonstration in the sunlight as described. Instead, the magician will perform the parlor trick entirely indoors where no sunlight can inadvertently ruin the trick. Then the magician will use smoke and mirrors to pretend that a lamp or a candle somehow "represents" the sun but only produces a very specific, and very narrowly focused frequency band that is needed to make the trick work. After performing the parlor trick and achieving the desired result, the magician says "See, this is what happens with the sun outdoors! The gullible audience that doesn't know the secret behind the trick is amazed and wants to pay more in taxes to save the planet.
Every time a magician performs the "levitate the assistant" trick, the assistant always appears to levitate, every time ... but it's a trick. Nobody can actually levitate.
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Nope. Wrong words. When you add thermal energy to CO2, it causes the CO2 to have more associated thermal energy. Of course, whatever quantity of thermal energy the CO2 has is radiating out of it freely, proportionally to its absolute temperature to the 4th power, in the form of thermal radiation (which is electromagnetic radiation).
ZenMode Error. You are once again treating the atmosphere as though it is not part of the earth.
Cleanly you didn't watch the MIT video where the amount of energy that reaches the thermopile at the end of the tube is being measured.
When air is pushed into the tube, there is no change in the amount of energy reaching the thermopile. When CO2 is pushed into the tube, there is a measurable change in the amount of energy reaching the thermopile. We should expect that to be the case because CO2 absorbs the energy, unlike air (primarily nitrogen and oxygen).
So if you are correct that everything absorbs energy, why is there a change when CO2 is introduced into the tube?
In case you care to actually watch the video:
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